請教簡單Shell問題 我想請教一下，怎樣當n2＝0的時候報錯，還有就是如何直接得到運行結果啊？ 我剛開始學習Shell，麻煩了 #!/bin/sh #Filename:calc.sh "Caculator:" while true do echo -n "a)+  s)-  m)*   d)/  q)=exit     " echo -n "input:" read op case $op in a) op="+" ;; s) op="-" ;; m) op="*" ;; d) op="/" ;; q) exit ;; *) echo "wrong ,input again..." continue ;; esac echo "input two numbers:" read n1 n2 echo -n "$n1""$op""$n2" RESULT=$[$n1$op$n2] echo "="$RESULT echo -n "continue (y/n)? " read answer case $answer in n) break;; y) continue;; *) echo "wrong input!! error!!!" break;; esac done 多謝 多謝 還有一個問題 Create a bash shell script that reads in a number from the user. If the number is 1, print out the date. If the number is 2, list the files in the current directory. If the number is 3, print out who is currently logged onto the system. If the number is anything else, print out an error message and exit. 不知道該如何做 謝謝！ --> :mrgreen:上面用了case還不知道怎麼做...... [code] function opt(){ read x; case $x in 1) date ;; 2) ls ;; 3) w ;; *) echo "Error";; esac; } [/code] 真的是初學阿， 還有就是，例如輸入ls後，能夠得知ls的參數的數量，不知道這個shell應該怎麼寫？ --> [code]echo "ls -l -x -a" |awk -F'-' '{print NF-1}'[/code]:?::mrgreen: % read x ls -l -x % $x g.py Tuc.dat % echo $x|awk -F'-' '{print NF-1}' 2 這也行啊 ls --help |grep '^ *-[a-zA-Z]' 把ls做一個變量就OK了,, [ 關閉窗口 ]