-- A new template of the Please help us to see where the wrong procedure should be grateful! #include<iostream> Template "typename any> Void swap (any &a, any &b) { Any temp; Temp=a; A=b; B=temp; } Int main () { Using namespace std; Cout.precision (2); Cout.setf (ios : : fixed, ios : : floatfield); Int i=10, j=20; Cout<< "i, j=" "<i<<", "" <j<<. " \n "; Cout<< "using compile-generated int swapper:\n"; Swap (i, j); Cout<< "now i, j=" "<i<<", "" <j<<. " \n "; Return 0 } LZ compiler not? : : Std a void swap<int> (_Ty &, _Ty &) and the same type you !ambiguous~ Be renamed Swap (i, j); Changed : : swap (i, j); Thank you! [ Closed window ]