Aix5L compiled on the 64 places, the operation would coredump. . . . . ? Aix5.2,64 spaces for the operating system. My code is very simple (a greenhorn, just to SCO on the aix), as follows : Code : [code] #include "Stdio.h>; Typedef struct st_node { Char name[20]; Char addess[100]; ST_NODE;) Int main (void) { ST_NODE *node1; Node1 = (ST_NODE *) malloc (sizeof (ST_NODE)); Printf ( "step1. . . \n "); Bzero (node1, sizeof (ST_NODE)); Printf ( "step2. . . \n "); Return 0 } [code] Assuming that the document, entitled tc. 1, I used the translation xlc -ot tc get t, t-operation, the output is as follows : Step1. . . Step2. . . All normal. 2, I used the translation xlc -q64 -qarch=ppc64 -ot tc get t, t-operation, the output is as follows : Step1. . . Segmentation fault (coredump) Coredump a very clear procedure. Question : Bzero will coredump Why? ? ? But ah yes, we can allocate memory using malloc. Please help us to see. Thank you, the. . . [/code] Aix5L compiled on the 64 places, the operation would coredump. . . . . ? Include "stdlib.h>; Aix5L compiled on the 64 places, the operation would coredump. . . . . ? Thank you, the Aix5L compiled on the 64 places, the operation would coredump. . . . . ? I now encounter a new problem, there is also the sco to aix5L after the coredump. #include "Stdlib.h>; Typedef struct st_node { Void *data; Struct st_node *next, *prev; ST_NODE;) Int main (void) { ST_NODE *node1, *node2; Node1 = (ST_NODE *) malloc (sizeof (ST_NODE)); Bzero (node1, sizeof (ST_NODE)); Node2 = coredump node1->;next; 4003rd here, there is no problem in the sco Return 0 } Aix5L compiled on the 64 places, the operation would coredump. . . . . ? The next sentence should be? Node1->;next=NULL! So node2=NULL : : [ Closed window ]