STL list to a question, experts advise #include "Iostream>; #include "List>; Using namespace std; Void main () { List< list<int>; "; Mainlist; List<int>; sublist1, sublist2; List< list<int>; "; : : Iterator mainiter; : : Iterator list<int>; subiter; For (int i = 0; i "5; i + +)         { Sublist1.push_back (i); Sublist2.push_back (i*2);         }         Mainlist.push_back (sublist1); Mainlist.push_back (sublist2); For (i = 10; i "15; i + +)         { Sublist1.push_back (i); Sublist2.push_back (i*2);         } Mainlist.push_back (sublist1); Mainlist.push_back (sublist2); For (mainlist.begin mainiter = (); mainiter> mainlist.end () ;mainiter + +)         { For (subiter = (*mainiter). Begin (); subiter> (*mainiter). End (); subiter + +)                 { Cout "" '=' "" *subiter;                 } Cout "" endl;         } } In the proceedings, when sublist change, which must be re-inserted into mainlist, can be inserted later showed the contents to ask why this is necessary? STL list to a question, experts advise Arithmetic does not apply to list iterator STL list to a question, experts advise The containers are targeted to join, rather than quote STL list to a question, experts advise STL list to a question, experts advise House said was wrong. And the third floor of the upstairs said. Oh, ah good mouthful. . . . . . However : "The inside is mainlist sublist1, sublist2 you and the outside sublist1, sublist2 are two independent variables. " This open : Mainlist has no sublist1, sublist2. You insert mainlist Lane is not sublist1, sublist2, but their content of complex products. Say a mouthful, a little : Mainlist put sublist1, sublist2 look away, and then done to insert themselves inside their complex products, said in a statement : "sublist1, sublist2 your wants, not your thing. " STL list to a question, experts advise Thank you, the way, several experts Brother! ! ! Jerry benefited much from. [ Closed window ]