Int * types of malloc is not free? #include "Stdio.h>; #include "Stdlib.h>; Main () { Int *g_link; Int *buf; Int Rifa G_link= (int *) malloc (10); Buf=g_link; LEAVES OF 13 SPECIES OF LAURACEAE free (buf); Position 1 */ For (i=0;i<=9;i++)         { *g_link=100000+i; G_link++;         } For (i=0;i<=9;i++)         { Printf ( "%d" *p+i);         } LEAVES OF 13 SPECIES OF LAURACEAE free (buf); Position 2 */ } In the above process, if at position 2 for free, will be incorrect report. Not one for free in the wrong position, and as usual in the free addresses for assignment. Is that the type int * malloc is not free? Int * types of malloc is not free? --> 10 What ah? Int * types of malloc is not free? [code]#include "Stdio.h>; #include "Stdlib.h>; Int main () { Int *g_link; Int *buf; Int Rifa G_link= (int *) malloc (sizeof (int) * 10); Free (g_link); Buf= (int *) malloc (sizeof (int) * 10); For (i=0;i<=5;i++) { * (Buf+i) =i; } For (i=6;i<=9;i++) { * (G_link+i) =i; } For (i=0;i<=9;i++) { Printf ( "%d" * (g_link+i)); } For (i=0;i<=9;i++) { Printf ( "%d" * (buf+i)); } Return 0 [/code]) Is the above code is. The only one you recall memory, but not like this genuine g_link or those that address. Int * types of malloc is not free? Into one location and the location of two no problem [code] #include "Stdio.h>; #include "Stdlib.h>; Main () { Int *g_link; Int *buf; Int Rifa         G_link= (int *) malloc (10); Buf=g_link;         LEAVES OF 13 SPECIES OF LAURACEAE free (buf); Position 1 */         For (i=0;i<=9;i++)         { *g_link=100000+i; G_link++;         }         G_link = buf;         For (i=0;i<=9;i++)         { Printf ( "%d" *g_link+i);         }         /*free (Buf); Position 2 */ Free (buf); } [/code] Int * types of malloc is not free? --> Do you have? Em06 : : Int * types of malloc is not free? Xhl read the code, it dawned on me that, indeed, should be malloc (10*sizeof (int)). Thank you upstairs [ Closed window ]