Gcc-s option is the stipped What does that mean? ? Gcc-s option is to strip the whole process, what does that mean? ? Prawn who gave me a detailed explanation. The final formation of the executable files with this option is not what kind of different? I found using s, or even impossible to use g LINUX track, saying that "no debugging symbols found" Who understand the prawn electricity gcc I do not quite understand. - S with less activation may be the only pre-compiler, and is a compendium of documents translated code. I know the strip is what the procedures were useless symbols are removed from the mess Similar slimming tool A strip of procedures They were to report the number of new debugging information on the left Nature can no longer gdb debugging S and implementation is the same strip and remove all symbols UGC! Procedures for the use of this option affect performance? If the procedures and enforceability s choice to help improve their performance? Reply to the message, the eighth floor BigMonkey It should not affect the performance of the process! The option was to remove the strip debugging process information! Even seldom used. Perhaps a bit of loading rate will improve then it may know : : Can largely reduce production target size embedded definitely S choice for the majority of the compiler have a choice, if we look at executable files on a clear, s not put debugging information removed, and also re-positioning table, string table also removed to achieve the goal of thin; Procedures size decreases, the process functions will not be affected. --> G debugging information is coupled with the oh Up Gentoo Lane make.conf used frequently mentioned the creation of SDR 's gcc' Optimization System --> If and when problems need to follow up on some of the little trouble. [ Closed window ]